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{{comic | number = 2060 | date = November 14, 2010 | title = 2010-11-14 | image = 20101114.gif | votey = 20101114after.gif | titletext = 2010-11-14 }} ==Explanation== {{incomplete}} ==Transcript== {{Computertranscript}} :[Describe panel here] :Maybe I'm just a naive undergrad, but you know what none of you "genius" economists account for in your equations: ?! The fact that you're fucking over the poor! :Iecon :My god. He's right. :All these years how could we :No, wait. Here itis. Page 862 :From eq. (11.2) it is clear that dp/di - ry 0 which quires :A(p-k) :(b,(p)-b.(p) :(11.3) :1-). :or if p is either 0 or 1 (because when P - 1.78 - y). When eq. (11.3)is satisfied, P is stationary because the effects of conformist transmission (the left hand side of eq. (11.3)) just offset the effects of differential payoffs (the right-hand side). Thus, in the presence of conformist trans-mission, and for p e (0,1), the equilibrium payoffs to the norm favored by conformism will always be less than the payoffs of the more preva lent norm. Figure 11.1 illustrates such an equilibrium. For p (0,1), dp/dr takes the sign of An equilibrium :is asymptotically stable (self if the derivative of cq. 11.2) with respect to p is negative, requiring that :db, :db, :A (foip) :(11.4a) :dp dp :A :(11.4b) :Caption: which is satisfied if the conformist advantage conferred on x by a small increase in p. namely NII A), is more than offset by the payoff ad-conferred on y by the same increase in p (the right-hand side). figure 11.1. p represents the solution to eq. (11.3) satisfying eq. 11.4a) and is hence a stable equilibrium distribution of norms. From eqs. (11.3) and (11.4a) we see that conformism has two effects. ==Votey Transcript== {{Computertranscript}} :[Describe panel here] :What a horrible 3 seconds {{comic discussion}}
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